For silver, `C_p(JK^(-1)mol^(-1))=23+0.01T` If the temperature (T) of 3 moles of silver is raised from 300 K to 1000 K at 1 atm pressure, the value of 'Delta H' will be close to

Options

A. 13kJ
B. 16kJ
C. 62kJ
D. 21kJ

Answer

C

Explanation

`Delta H = int_(T_1)^(T_2) n CpdT = n int_300^1000 (23 + 0.01T)dT`
`=3[23T + (0.01T^2)/2]_300^1000 = 3 [(2 xx 23 xx700 + 9100)/2]`
` = 61950 J // mol~~ 62 kJ //mol`.