Home
Class 11
CHEMISTRY
The enthalpy of dissolution of BaCl(2)(s...

The enthalpy of dissolution of `BaCl_(2)(s) and BaCl_(2).2H_(2)O` are -20.6 and 8.8 KJ `mol^(-1)` respectively . Calculate enthalpy of hydration forgiven reaction:
`BaCl_(2)(s)+2H_(2)OtoBaCl_(2).2H_(2)O(s)`

A

29.4 kJ

B

– 11.8 kJ

C

– 20.6 kJ

D

– 29.4 kJ

Text Solution

Verified by Experts

The correct Answer is:
D
(i) `BaCl_2(s) to BaCl_2(aq) , Delta H =-20.6 kJ//mol`
(ii) `BaCl_2. 2H_2O (s) to BaCl_2(aq) + 2H_2O(l) , Delta H, = 8.8 kJ//mol`
Subtracting eq.(ii) from eq.(i)
`BaCl_2(s) + 2H_2O(l) to BaCl_2 . 2H_2O(s)`
`DeltaH = (-20.6 - 8.8) kJ//mol`
`DeltaH = - 29.4kJ//mol`.
Promotional Banner

Similar Questions

Explore conceptually related problems

Enthalpies of solution of BaCl_(2)(s) and BaCl_(2).2H_(2)O(s) are -20 kJ//"mole" and 8.0kJ//"mole" respectively. Calculate heat of hydration of BaCl_(2)(s) .

Enthalpy of solution for BaCI_(2). 2H_(2)O and BaCI_(2) are 18.8 and -30.6 kL mol^(-1) respectively. Calculate the enthalpy of hydration of BaCI_(2) to BaCI_(2). 2H_(2)O .

Enthalpies of solution of BaCI_(2). 2H_(2)O and BaCI_(2) are 8.8 and -20.6 kJ mol^(-1) respectively.Calculate the heat of hydration of BaCI_(2). 2H_(2)O

Ethalpies of solution of BaCI_(2)(s) and BaCI_(2).2H_(2)O(s) are -20.0kJ mol^(-1) and 8.0 kJ mol^(-1) , respectively. Calculate Delta_(hyd)H^(Theta) of BaCI_(2) to BaCI_(2).2H_(2)O .

The heat of solution of BaCl_(2) .2H_(2) O_((s)) and anhydrous BaCl_(2(s)) are 8.37" kJ mol"^(–1) and –20.62" kJ mol"^( –1) respectively then heat of hydration of BaCl_(2(s)) will be :-

DeltaH_(t)^(@) for CO_(2)(g) and H_(2)O(g) are -393.5, -110.5 and -241.8 kJ"mol"^(-1) respectively. The standard enthalpy change (in kJ) for the reaction. CO_(2)(g) + H_(2)(g) to CO(g) + H_(2)O(g) is: