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For the process : H(2)O(l) (1 bar, 373...

For the process :
`H_(2)O(l) (1 bar, 373 K) to H_(2)O(g) (1 bar, 373 K)`, the correct set of thermodynamic parameters is :

A

`DeltaG = 0, DeltaS = +ve`

B

`DeltaG = 0, DeltaS = -ve`

C

`DeltaG = +ve , DeltaS = 0`

D

`DeltaG = -ve, DeltaS = +ve`

Text Solution

Verified by Experts

The correct Answer is:
A
Since, liquid is passing in to gaseous phase so entropy will increase and at 373 K the phase transformation remains at equilibrium. So `DeltaG = 0`.
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