For a particular reversible reaction at temperature T, `DeltaHandDeltaS` were found to be both +ve. If `T_(e)` is the temperature at equilibrium, the reaction would be spontaneous when

Options

A. `T=T_(e)`
B. `T_(e)gtT`
C. `T gt T_(e)`
D. `T_(e)` is 5 time T

Answer

C

Explanation

At temperature T :
`DeltaG = DetlaH - T DeltaS`
At temperature `T_e `:
`DeltaG_e = DeltaH - T_e DeltaS = 0`
`DeltaH = T_e DeltaS`
`DeltaG = T_eDeltaS - TDeltaS`
As `DeltaS` is positive and `T gt T_e` then `Delta G lt 0`.