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Lattice enthalpy and enthalpy of solutio...

Lattice enthalpy and enthalpy of solution of NaCl are 788 `kJ"mol"^(-1)` and `4kJ"mol"^(-1)` respectively. The hydration enthalpy of NaCl is

A

`− 780kJ mol^(−1)`

B

`780kJ mol^(−1)`

C

`− 784 kJ mol^(−1)`

D

`784 kJ mol^(−1)`

Text Solution

Verified by Experts

The correct Answer is:
C
`Delta_(Sol) H^@ = Delta_("lattice")H^@ + Delta_("Hyd.")H^@`
`4 = 788 + Delta_("Hyd.")H^@`
`Delta_("Hyd.")H^@ = - 784kJ//mol`.
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