Home
Class 11
CHEMISTRY
If the standard molar enthalpy change fo...

If the standard molar enthalpy change for combustion of graphite powder is `-2.48 xx 10^(2)kJ mol^(-1)`, the amount of heat generated on combustion of 1g of graphite powder is ______kJ. (Nearest integer).

Text Solution

Verified by Experts

The correct Answer is:
21

`underset("1 gram")(C("graphite")) + O_2 to CO_2(g) , DeltaH = - 2.48 kJ" mole"`
Total heat released `= 2.48 xx 1/12 xx 10^2`
` = 20.67 = 21`.
Promotional Banner

Similar Questions

Explore conceptually related problems

The heat of combustion of methane is -880 KJ mol^(-1) . The quantity of heat liberated in the combustion of 3.2 g methane is

If the enthalpy of combustion of C (graphite) is -393.3kJ mol^(-1) , then for producing 39.3kJ of heat the amount of carbon required is

The standard heat of combustion of graphite carbon is -393.5 kJ mol^(-1) . The standard enthalpy of CO_(2) is

If the heat of combustion of pentane is 3507 kJ mol^(-1) then its calorific value will be ?

The heat of combustion of CH_(4) is -400 KJ mol^(-1) . Calculate the heat released when 40g of H_(2)O is formed upon combustion :-

If the enthalpy of combustion of diamond and graphite are -395.4 kJ mol^(-1) and -393.6 kJ mol^(-1) , what is enthalpy change for the C("graphite") rarr C("diamond") ?