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At 25^(@)C, 50 g of iron reacts with HCl...

At `25^(@)C`, 50 g of iron reacts with HCl to form `FeCl_(2)`. The evolved hydrogen gas expands against a constant pressure of 1 bar. The work done by the gas during this expansion is
(Round off to the Nearest Integer).
[Given : `R=8.314 J mol^(-1)K^(-1)` . Assume, hydrogen is an ideal gas]
[Atomic mass of Fe is 55.85 u]

Text Solution

Verified by Experts

The correct Answer is:
2218
`Fe + 2 HCl to FeCl_2 + H_2`
` 50/55.85` moles
No. of `H_2` produced ` = 50/55.85` moles
Work done `= - P_("ext". DeltaV)`
`= Deltan_g RT`
`= 50/55.85 xx 8.314 xx 298`
`~= 2218J`.
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