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In the following compound, the number of...

In the following compound, the number of ‘sp’ hybridized carbon is
`CH_(2)= C = CH - underset(CN)underset(|)( C)H - C-= CH`

A

2

B

3

C

4

D

5

Text Solution

Verified by Experts

The correct Answer is:
C
`H_(2) C= overset(sp) (C ) = CH- underset(sp) underset(C ) underset(|) ( C) H - overset(sp) (C ) -= overset(sp) ( C) H`
`implies` No. of sp hybridized C= 4
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