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The correct order of leaving group abili...

The correct order of leaving group ability in a nucleophilic substitution reaction is

A

`Br^(-) gt Cl^(-) gt CH_(3) CO_(2)^(-) gt HO ^(-) gt H^(-)`

B

`H^(-) gt OH^(-) gt CH_(3) CO_(2)^(-) gt Cl^(-) gt Br^(-)`

C

`Br^(-) gt CH_(3)CO_(2)^(-) gt Cl^(-) gt OH^(-) gt H^(-)`

D

`CH_(3) CO_(2)^(-) gt Br^(-) gt Cl^(-) gt OH^(-) gt H^(-)`

Text Solution

Verified by Experts

The correct Answer is:
A
A leaving group is a molecular fragment that departs with a pair of electrons in heterolytic bond cleavage. The weaker the base, the better the leaving group.
Br- and Cl- are both excellent leaving group with Br- being better than `Cl- CH_(3) COO`-are moderate leaving group. OH- is a strong base hence it is a poor leaving group. H- is an extremely poor leaving group as it a very strong base
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