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The number of optical isomers of CH3CH(O...

The number of optical isomers of `CH_3CH`(OH)CH(OH)CHO is :-

A

Zero

B

2

C

3

D

4

Text Solution

Verified by Experts

The correct Answer is:
D
`CH_(3) - overset(H)overset(|)underset(OH)underset(|)(C^(**)) - overset(H)overset(|)underset(OH)underset(|)(C^(**)) - CHO`
It has 2 optically active carbon atoms and it has no plane of symmetry. So, number of optical isomers = `2^(2) = 4`
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