The number of possible isomers for compound `C_(2) H_(3) Cl_(2) Br` is

Options

A. 2
B. 3
C. 4
D. 5

Answer

C

Explanation

Following 4 isomers are possible:
`H_(3)C - overset(Cl)overset(|)underset(Cl) underset(|)( C) - Br " " BrH_(2) C - overset(Cl) overset(|)underset(Cl) underset(|) ( C)H`
`Cl - overset(H)overset(|)underset(H)underset(|)( C) - overset(Cl)overset(|)underset(Br) underset(|)( C^(**)) -H` (d and l-form)
Due to presence of a chiral carbon, 2 optical isomers are possible