The total number of acyclic isomers, including the stereoisomers, with formula `C_(4)H_(7)Cl` is

Options

A. 11
B. 12
C. 9
D. 10

Answer

B

Explanation

`C_(4) H_(7) Cl` is a monochloro derivative of `C_(4) H_(8)` which itself exists in three isomeric forms . (i) `CH_(3) - CH_(2) - CH = CH_(2)`, its possible mono-chloro derivates are :
`CH_(3)- CH_(2) - CH = CH - Cl`
2 isomers : cis and trans forms
`CH_(3)-overset(**) underset(Cl) underset(|) (C ) - CH = CH_(2)`
optically active (exists) in two forms)
`ClCH_(2) - CH_(2) - CH= CH_(2)` (one form)
`H_(3) C - CH_(2) -overset(Cl)overset(|)( C)= CH_(2)` (one form )
(ii) `CH_(3) - CH = CH - CH_(3)` : Its possible monochloro derivates are : `CH_(3) - CH = underset(Cl) underset(|) ( C) - CH_(3)`
Exists in two geometrical forms
`CH_(3) - CH = CH - CH_(2)Cl`
Exists in two geometrical forms
(iii) `CH_(3) - underset(CH_(3))underset(|)( C) = CH_(2)` , its possible monochloro derivatives are `CH_(3) - underset(CH_(3))underset(|)( C) = CH - Cl , Cl CH_(2)- underset(CH_(3))underset(|)( C) = CH_(2)`
Thus , the total acyclic isomers forms of `C_(4) H_(7) Cl` are 12.