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The total number of acyclic isomers, inc...

The total number of acyclic isomers, including the stereoisomers, with formula `C_(4)H_(7)Cl` is

A

`{:("Geometrical" ,, "Optical") , (6 ,,2):}`

B

`{:("Geometrical" ,, "Optical") , (4 ,,2):}`

C

`{:("Geometrical" ,, "Optical") , (6 ,,0):}`

D

`{:("Geometrical" ,, "Optical") , (4 ,,0):}`

Text Solution

Verified by Experts

The correct Answer is:
A
`CH_(3) - CH_(2) - CH = CHCl` (cis and trans form)
`CH_(3)- CH = CH - CH_(2) Cl` (cis and trans form)
`CH_(3) - CH = C - Cl - CH_(3)` (cis and trans form)
`H_(2) = underset(CH_(3))underset(|)( C) - CH_(2) - Cl` (No stereo-isomers)
`H_(2) C = CH -overset(H)overset(|) underset(Cl)underset(|)( C^(**)) - CH_(3)` (2 optical isomers)
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