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Elimination of bromine from 2-bromobutan...

Elimination of bromine from `2-`bromobutane results in the formation of

A

Equimolar mixture of 1 and 2-butene

B

Predominantly 2-butene

C

Predominantly 1-butene

D

Predominantly 2-butyne

Text Solution

Verified by Experts

The correct Answer is:
B
`{:(beta_2" "alpha" "beta_1),(CH_3-CH - CH_2 -CH_3underset(-HBr)toCH_3 - CH = CH - CH_3),(" "|),(" "Br),("2-bromobutane" " 2-butene"):}`
The resulting product will be predominantly but–2–ene as per Saytzeff’s rule.
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