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HBr reacts with CH2=CH-OCH3 under anhydr...

HBr reacts with `CH_2=CH-OCH_3` under anhydrous condditions at room temperature to give

A

`CH_3 CHO and CH_3 Br`

B

`BrCH_2 CHO and CH_3 OH`

C

`Br CH_2 - CH_2 - OCH_3`

D

`H_3 C - CHBr - OCH_3`

Text Solution

Verified by Experts

The correct Answer is:
D
Since the reaction is taking place under anhydrous conditions. So there is no question of bond cleavage around etheric oxygen.
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