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The reaction of CH(3)CH=CH(2) with HOCl ...

The reaction of `CH_(3)CH=CH_(2)` with HOCl will yield

A

`CH_(3) - CHCl - CH_(2) OH`

B

`CH_(3) - underset(OH)underset(|)CH-CH_(2) - Cl`

C

`CH_(3) - CH_(2) - CH_(2) - COCl`

D

`CH_(3) - overset(Cl)overset(|)underset(OH)underset(|) - CH_(3)`

Text Solution

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The correct Answer is:
B

`CH_(3)-underset("Propene")(CH=CH_(2))+HOCl rarr CH_(3)-underset("1-chloropropan")(CH-underset(OH)underset(|)(CH_2)-Cl)`
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