The addition of HBr of 1-butene gives a mixture of products A,B and C

(C) `CH_(3)-CH_(2)-CH_(2)-CH_(2)-Br`
The mixture consists of

Options

A. A and B as major and C as minor products
B. B as major, A and C as minor products
C. B as minor, A and C as major products
D. A and B as minor and C as major products

Answer

A

Explanation

The alkene is unsymmetrical, hence will follow Markownikoff’s rule to give major product
`underset("Butene-1")(CH_(3)-CH_2)-CH = CH_2 + H-Br rarr CH_(3)-CH_(2)-underset((A))(CHBr)-CH_3+C_2H_5-overset(Br)overset(|)underset((B))underset(H)underset(|)(C^(**))-underset("(C) (minor product)")(CH_3 + CH_(3)-CH_(2)-CH_(2)-CH_(2)Br)`
Since, I contains, a chiral carbon, it exists in two enantiomers A ( and ) B which are mirror images of each other