When sulphur dioxide is passed in an acidified `K_2Cr_2O_7` solution,the oxidation state of sulphur is changed from

Options

A. + 4 to + 6
B. + 6 to + 4
C. + 4 to 0
D. + 4 to + 2

Answer

A

Explanation

`K_2Cr_2O_7` acts as a strong oxidising agent. It oxidises other compounds and gets itself reduced. In `SO_2,S` is in + 4 state so it gets oxidised to +6 state which is maximum group oxidation state.