Home
Class 12
CHEMISTRY
In aqueous solution Cr^(2+) is stronger ...

In aqueous solution `Cr^(2+)` is stronger reducing agent than `Fe^(2+)`. This is because

A

`Cr(2+)`ion is more stable than `Fe^(2+)`

B

`Cr^(3+)` ion with `d^3` configuration has favourable crystal field stabilisation energy

C

`Cr^(3+)` has half-filled configuration and hence more stable

D

`Fe^(3+)` in aqueous solution is more stable than`Cr^(3+)`

Text Solution

Verified by Experts

The correct Answer is:
B

Half – filled `(t_(2g)^3)` configuration has favourable crystal field stabilizing energy. So `Cr^(2+)` can readily form `Cr^(3+)`, being a strong reducting agent.
Promotional Banner

Similar Questions

Explore conceptually related problems

F_(2) is a stronger oxidising agent than Cl_(2)

In aqueous solution , chlorine is a stronger oxidising agent than fluorine.

Which of the following statements is correct ? (1) The highst oxidation state of a metal is either xhibited in its oxide or its fluoride (2) Cr^(2+) is a stronger reducing agent than Fe^(2+) (3) The stability of the +6 state for Group 6 elements W^(6+) lt Mo^(6+) lt Cr^(6+) (4) Cu^(+) ion is not stable in aqueous solutions

In aqueous solution, H_(2) will not reduce :

Explain the following observations : (i) Copper atom has completely field d orbitals (3d^(10)) in its ground state, it is regarded as a transition element. (ii) Cr^(2+) is a stronger reducing agent than Fe^(2+) in aqueous solutions.

Assertion: HgCl_(2) and SnCl_(2) cannot exist together in an aqueous solution. Reason: SnCl_(2) is a strong reducing agent because Sn shows inert part effect.

Li is very strong reducing agent in aqueous solution because of -