Higher oxidation state of manganese in fluoride is `+4 (MnF_(4))` but highest oxidation state in oxides is `+7(Mn_(2)O_(7))` because

Options

A. Fluorine is more electronegative than oxygen
B. Fluorine does not possess d orbitals
C. Fluorine stabilises lower oxidation state
D. In covalent compounds, fluorine can form single bond only while oxygen forms double bond

Answer

D

Explanation

Highest oxidation state of manganese in fluoride is ` + 4(MnF_4)` but highest oxidation state in oxides is ` + 7(Mn_2O_7)`. The reason is that in covalent compounds fluorine can form single bond while oxygen forms double bond.