If excess of NH(4)OH is added to CuSO(4)...

If excess of `NH_(4)OH` is added to `CuSO_(4)` solution, it forms blue coloured complex which is

A

`Cu(NH_3)_4SO_4`

B

`Cu(NH_3)_2SO_4`

C

`Cu(NH_4)_4SO_4`

D

`Cu(NH_4)_2SO_4`

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The correct Answer is:

A

`CuSO_4 + 4NH_4OH to underset("Blue")([Cu(NH_3)_4]SO_4) + 4H_2O`

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