The number of electrons required to ...

The number of electrons required to reduce chromium completely in `Cr_(2) O_(7) ^(2-) ` to `Cr_(3+)` in acidic medium , is

A

5

B

3

C

6

D

2

Verified by Experts

The correct Answer is:

C

`Cr_2O_7^(2-) + 14 H^(+) + 6e^(-) to 2Cr^(3+) + 7H_2O`

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