The spin magnetic moment of cobalt in the compound `Hg[Co(SCN)_(4)]` is

Options

A. `sqrt3 `
B. `sqrt8`
C. `sqrt15`
D. `sqrt24`

Answer

C

Explanation

In this complex `Co^(2+)` ion have 3 unpaired electron so spin only magnetic moment will be `mu = sqrt(n(n + 2))`
Where n = no. of unpaired `e^(-)`.
`sqrt(3 (3 + 2)) i.e., sqrt15` B.M.