Reaction of `t-butyl` bromide with sodium methoxide produces

Options

A. Isobutane
B. Isobutylene
C. Sodium t-butoxide
D. t-butyl methyl ether

Answer

B

Explanation

`CH_3-overset(CH_3)overset(|)underset(CH_3)underset(|)(C)-Br+CH_3ONa overset("Elimination")(rarr) CH_3-underset("Isobutylene")overset(CH_3)overset(|)(C)=CH_2+CH_3OH+NaBr`
`CH_3ONa rarr CH_3O^(-)+Na^(+)`
methoxide ion `(CH_3O^(-))` is a strong base, therefore it abstract proton from `3^@` alkyl halide and favours elimination reaction.