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Given the polymers (i) Nylon 66, (ii) Bu...

Given the polymers (i) Nylon 66, (ii) Buna-S , (iii) Polythene , arrange these in increasing of their inter-molecular forces (lower to high)

A

(i) `gt `(ii) `gt` (iii)

B

`(ii) gt (iii) gt (i)`

C

`(ii) lt (iii) lt (i)`

D

`(iii) lt (i) lt (ii)`

Text Solution

Verified by Experts

The correct Answer is:
C
Nylon 66 is a fibre and has hydrogen bonding as intermolecular force. Buna – S is an elastomer and has weak Vander Waal’s forces.
Polythene is thermoplastic and has intermediate intermolecular forces. (i.e. stronger than elastomer but weaker than fibre).
Thus, the order of intermolecular forces is
`underset("(ii)")(Buna -S) lt underset("(iii)")("Polythene") lt underset("(i)")("Nylon")`
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