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The reaction .(5)B^(8) rarr .(4)Be^(8) +...

The reaction `._(5)B^(8) rarr ._(4)Be^(8) + ._(1)e^(0)` is due to

A

Loss of `alpha` particles

B

Loss of `beta `- particles

C

Loss of positron

D

Electron loss

Text Solution

Verified by Experts

The correct Answer is:
C
The emission of positron takes place.
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