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In the nuclear reaction Mg12^(24) + He2^...

In the nuclear reaction `Mg_12^(24) + He_2^4 to n_0^1 + (?)` The product nucleus is

A

`""_(13)Al^(27)`

B

`""_(14)Si^(27)`

C

`""_(13)Al^(38)`

D

`""_(12)Mg^(25)`

Text Solution

Verified by Experts

The correct Answer is:
B
`""_(12)Mg^(24) + ""_(2)He^4 to ""_(0)n^1 + ""_(14)Si^(27)`
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