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Calculate mass defect in the following r...

Calculate mass defect in the following reaction: `H_1^2 + H_1^3 to He_2^4+n_0^1`
(Given: mass `H^(2) = 2.014 am u, H^3 = 3.016 `amu He= 4.004,n =1.008amu)

A

0.018 amu

B

0.18 amu

C

0.0018 amu

D

1.8 amu

Text Solution

Verified by Experts

The correct Answer is:
A
Mass loss = mass of reactant – mass of product.
`= (2.014 + 3.016)- (4.004 + 1.008) `
= 5.030-5.012 = 0.018 amu
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