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.(88)^(228) X - 3 alpha - beta to Y. The...

`._(88)^(228) X - 3 alpha - beta to Y`. The element Y is:

A

`""_(82)Pb^(216)`

B

`""_(82)Pb^(217)`

C

`""_(83)Bi^(218)`

D

`""_(83)Bi^(216)`

Text Solution

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The correct Answer is:
D

Atomic No. : `88 -(3xx2) + (1xx1) = 83`
Mass No. : `228 - (3xx4) - (1xx 0) = 216`
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