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C^(14) is radioactive. The activity and ...

`C^(14)` is radioactive. The activity and the disintegration product are

A

`beta`-active , `""_(7)N^(14)`

B

`alpha`-active, `""_(7)Be^(10)`

C

Positron active ,` ""_(5)B^(14)`

D

`gamma` -active , `C^(14)`

Text Solution

Verified by Experts

The correct Answer is:
A
`""_(6)C^(14) to ""_(7)N^(!4) + ""_(-1)e^0` , `beta`-active
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