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After the emission of alpha-particle fro...

After the emission of `alpha`-particle from the atom `X_92^238`, the number of neutrons in the atom will be

A

138

B

140

C

144

D

150

Text Solution

Verified by Experts

The correct Answer is:
C
`""_(92)X^(238) overset(-alpha)to ""_(90)Y^(234)`
Number of neutrons = 234-90 =144
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