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.(84)Pb^(219) is a member of actinium se...

`._(84)Pb^(219)` is a member of actinium series. The other member of this series is

A

`""_(89)Ac^(225)`

B

`""_(90)Th^(232)`

C

`""_(15)P^(35)`

D

`""_(92)U^(235)`

Text Solution

Verified by Experts

The correct Answer is:
D
The series 4n + 3 is known as actinium series. It shows that if mass number is divided by 4 then the remainder must be 3. Hence, the another member of this series is `""_(92)U^(235)`.
`because (235)/(4) = 58` + Remainder 3 .
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