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After emission of one alpha particle fol...

After emission of one `alpha` particle followed by one `beta`-particle from `""_(92)^(238)X`, the number of neutrons in the atom will be

A

142

B

146

C

144

D

143

Text Solution

Verified by Experts

The correct Answer is:
D
`""_(92)X^(238) overset(-alpha)to ""_(90)Y^(234) overset(-beta)to ""_(91)Z^(234)`
Number of neutrons = 234-91 =143
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