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What is the symbol for the nucleus remai...

What is the symbol for the nucleus remaining after `._(20)Ca^(42)` undergoes `beta-`emission

A

`""_(21)Ca^(42)`

B

`""_(20)Sc^(42)`

C

`""_(21)Sc^(42)`

D

`""_(21)Sc^(41)`

Text Solution

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The correct Answer is:
C
`""_(20)Ca^(42) to ""_(21)Sc^(42) + ""_(-1)e^0`
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