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The number of alpha- and beta-particles ...

The number of `alpha- and beta-`particles emitted when a radioactive element `._(90)E^(322)` changes into `._(86)G^(220)` will be

A

5 and 4

B

2 and 3

C

3 and 2

D

4 and 1

Text Solution

Verified by Experts

The correct Answer is:
C

`""_(90)E^(232) to ""_(86)G^(220)`
No. of `alpha` particle `= (232-220)/(4) = 3`
No. of `beta` particle = 86-[90-2x3]= 2
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