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The nuclear binding energy for Ar (39.96...

The nuclear binding energy for Ar (39.962384 amu) is : (given mass of proton and neuron are 1.007825 amu and 1.008665amu respectively)

A

343.62 MeV

B

0.369096 MeV

C

931 MeV

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
A
`""_(18)Ar^(40)`
Total no. of protons = 18
Total no. of neutrons = 22
Mass defect = `[mxx p + mxx n]` - 39.962384
`=[1.007825 xx 18+1.008665 xx 22]-39.962384`
= [18.14085 + 22.19063] - 39.962384 = 0.369
Binding energy = mass defect `xx` 931
`=0.369 xx 931 = 343.62 ` MeV
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