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The number of neutrons in the parent nuc...

The number of neutrons in the parent nucleus which gives `N^14` on `beta`-emission and the parent nucleus is

A

`8, C^(14)`

B

`6, C^(12)`

C

`4, C^(13)`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
A
`""_(6)C^(14) to ""_(7)N^(14) + ""_(-1)beta^0`
no. of neutrons in `C^(14)` = 14-6= 8
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