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A radioactive substance has t(1//2) 60 m...

A radioactive substance has `t_(1//2)` 60 minutes. After 3 hrs, what precentage of radioactive substance will remain

A

`50%`

B

`75%`

C

`25%`

D

`12.5`

Text Solution

Verified by Experts

The correct Answer is:
D
3 hrs = 3 half life periods
`N/N_0 = (1/2)^n`
`= (1/2)^3`
`1//8` = 12.5 %
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