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In the case of a radioisotope , the valu...

In the case of a radioisotope , the value of `t_(1//2)` and `lambda` are identical in magnitude. The value is

A

0.693

B

`(0.693)^(1//2)`

C

`1/(0.693)`

D

`(0.693)^2`

Text Solution

Verified by Experts

The correct Answer is:
B

`t_(1//2) = (0.693)/(k "or" lambda) ` , i.e., 0.693 `= lambda^2 implies lambda = (0.693)^(1//2)`
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