Home
Class 12
CHEMISTRY
The decay constant of Ra^(226) is 1.37xx...

The decay constant of `Ra^(226)` is `1.37xx10^(-11)s^(-1)`. A sample of `Ra^(226)` having an activity of `1.5` millicurie will contain

A

`4.1 xx 10^(18)`

B

`3.7 xx 10^(17)`

C

`2.05 xx 10^(15)`

D

`4.7 xx 10^(10)`

Text Solution

Verified by Experts

The correct Answer is:
A
1 milli curie `= 3.7xx10^7` dps
1.5 milli curie `=5.55xx10^(7) ` dps
`(5.55xx10^7)/(N_0) = lambda = 1.37 xx 10^(-11)`
Promotional Banner

Similar Questions

Explore conceptually related problems

The value of decay constant of Co^(60) is 2.5xx 10^(-7)"min"^(-1) . The activity of 2.0 g of the sample is nearly :

They decay constant of radioactive element is 1.5xx10^(9)s^(-1) Its mens-life (in second) will be

The decay constant for the radioactive nuclide 64Cu is 1.516 xx 10^(-5) s^(-1) . Find the activity of a sample containing 1mug of ^64Cu . Atomic weight of copper = 63.5 g mole^(-1) . Neglect the mass difference between the given radioisotope and normal coper.

The decay constant for an alpha- decay of Th^(232) is 1.58xx10^(-10)s^(-1) . How many alpha- decays occur from 1 g sample in 365 deys ?

What mass of Ra^(226) whose t_(1//2) = 1620 years will give the activity of 1 millicurie?

Decay constant of a reaction is 1.1 xx 10^(-9)//sec , then the half-life of the reaction is

One gram of .^(226)Ra has an activity of nearly 1 Ci. The half life of .^(226)Ra is,