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The half life period of Pb^(210) is 22 y...

The half life period of `Pb^(210)` is 22 years. If `2 g` of `Pb^(210)` is taken, then after 11 years the amount of `Pb^(210)` will be present is

A

1.414 g

B

2.428 g

C

3.442 g

D

4.456 g

Text Solution

Verified by Experts

The correct Answer is:
A
`N_t = N_0 (1/2)^2 [therefore t_(1//2)= 22 "years" , T = 11 "years", N_0 = 2, N_t =? ]`
`T= t_(1//2) xx n , 11 = 2 xx n "or " n = (11)/(22) = 1/2`
`therefore N_t = 2g xx (1/2)^(1//2) = 1.414 g `
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