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Radioactivity of a radioactive element r...

Radioactivity of a radioactive element remains `1//10` of the original radioactivity after `2.303` seconds. The half life period is

A

2.303

B

0.2303

C

0.693

D

0.0693

Text Solution

Verified by Experts

The correct Answer is:
C
`2.303 = (2.303)/(0.693) xx t_(1//2) log 10 `
`because N = (N_0)/(10) therefore N_0/N = 10`
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