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A radioactive isotope decays to such a r...

A radioactive isotope decays to such a rate that after 96 min only 1/8th of the original amount remains. The value `t_(1//2)` of this nuclide is

A

12

B

24

C

32

D

48

Text Solution

Verified by Experts

The correct Answer is:
C
`lambda = (2.303)/(t) log ([N_0])/([N]) = (2.303)/(96) log (1)/(1//8)`
`= (2.303)/(98) xx 0.9 = 0.0216`
`therefore t_(1//2) = (0.693)/lambda = (0.693)/(0.0216) = 32.0 `min
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