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If the disintegration constant is 6.93 x...

If the disintegration constant is `6.93 xx 10^(-6) yr^(-1)`, then half-life of `._(6)C^(14)` will be

A

`10^2 ` yr

B

`10^3` yr

C

`10^4` yr

D

`10^5` yr

Text Solution

Verified by Experts

The correct Answer is:
D
`t_(1//2) = (0.693)/(k) = (0.693)/(6.93 xx 10^(-6)) = 0.1 xx 10^6 = 10^5 ` yr
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