The half life of `""_(6)C""^(14)`, if decay constant `6.31xx10^(-4)` is

Options

A. 1098 yr
B. 109.8 yr
C. 10.98 yr
D. 1.098 yr

Answer

A

Explanation

`t_(1//2) = (0.693)/(k) = (0.693)/(6.31 xx 10^(-4)) = 0.1098 xx10^4 = 1098 ` yr