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The activity of a radioactive nuclide is...

The activity of a radioactive nuclide is `2 xx 10^(7)` disintegrations per minute (dpm). After 23.03 minutes, its activity is reduced to `2 xx 10^(6)` dpm. What is the average life (in min) of this nuclide

A

1000

B

10

C

1

D

0.1

Text Solution

Verified by Experts

The correct Answer is:
B
`t= (2.303)/(lambda) log (N_0)/(N)`
or `lambda = (2.303)/(t) log"" (N_0)/(N) = (2.303)/(23.03) log"" (2xx10^(7))/(2xx10^6)`
or `lambda = 0.1 "min"^(-1)`
Now, average life `=1/lambda = 1/(0.1) = 10 ` min
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