The `C^(14) " to " C^(12)` ratio in a wooden article is 13% that of the fresh wood. Calculate the age of the wooden article. Given that the half-life of `C^(14)` is 5770 years

Options

A. 16989 years
B. 16858 years
C. 15675 years
D. 17700 years

Answer

A

Explanation

`N/N_0 = (1/2)^((T)/(t_(1//2))) implies (13)/(100) = (1/2)^((T)/(5770))`
Taking log `implies log (13)/(100) = T/(5770) log 1//2 implies 16989 ` yrs.