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.(13)Al^(28) when radiated by suitable p...

`._(13)Al^(28)` when radiated by suitable projectile gives `._(15)P^(31)` and neutron. The projectile used is

A

Proton

B

Neutron

C

Alpha particle

D

Deuteron

Text Solution

Verified by Experts

The correct Answer is:
C
`""_(13)Al^(28)+ ""_(2)He^4 to ""_(15)P^(31) + ""_(0)n^(1)`
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