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.^(23) Na is the more stable isotope of ...

`.^(23)` Na is the more stable isotope of Na. Find out the process by which `._(11)^(24)` Na can undergo radioactive decay.

A

`beta^(-1)` emission

B

`alpha` emission

C

`beta^+` emission

D

K electron capture

Text Solution

Verified by Experts

The correct Answer is:
A
`""_(11)^(23)Na to n/p` ratio = 12/11
`""_(11)^(24)Na to n/p` ratio = 13/11
To decrease in `n/p` ratio gives out `beta^-` particle
`n to p + e(beta^-)`
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