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.(13)Al^(27) is a stable isotope. .(13)A...

`._(13)Al^(27)` is a stable isotope. `._(13)Al^(29)` is expected to disintegrate by

A

`alpha`-emission

B

`beta`-emission

C

Positron emission

D

Proton emission

Text Solution

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The correct Answer is:
B
The `n/p` ratio of `""_(13)Al^(29)` places it above the belt stability and thus it emits `beta`-particles.
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